38=-0.03x^2+x

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Solution for 38=-0.03x^2+x equation: 



38=-0.03x^2+x

We move all terms to the left:

38-(-0.03x^2+x)=0

We get rid of parentheses

0.03x^2-x+38=0

We add all the numbers together, and all the variables

0.03x^2-1x+38=0

a = 0.03; b = -1; c = +38;
Δ = b2-4ac
Δ = -12-4·0.03·38
Δ = -3.56
Delta is less than zero, so there is no solution for the equation

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